1¡¢Ñ¡ÔñÌâ  ±»³ÆΪÍòÄÜ»¹Ô­¼ÁµÄNaBH4ÈÜÓÚË®²¢ºÍË®·´Ó¦£ºNaBH4+2H2O¨TNaBO2+4H2¡ü£¬ÏÂÁÐ˵·¨ÖÐÕýÈ·µÄÊÇ£¨NaBH4ÖÐHΪ-1¼Û£©£¨¡¡¡¡£©
A£®NaBH4¼ÈÊÇÑõ»¯¼ÁÓÖÊÇ»¹Ô­¼Á
B£®NaBH4ÊÇÑõ»¯¼Á£¬H2OÊÇ»¹Ô­¼Á
C£®NaBH4ÖÐÅðÔªËر»Ñõ»¯£¬ÇâÔªËر»»¹Ô­
D£®±»Ñõ»¯µÄÔªËØÓë±»»¹Ô­µÄÔªËØÖÊÁ¿Ö®±ÈΪ1£º1

2¡¢Ñ¡ÔñÌâ  ÏÂÁз´Ó¦ÖУ¬¼ÈÊÇ»¯ºÏ·´Ó¦£¬ÓÖÊÇÑõ»¯»¹Ô­·´Ó¦µÄÊÇ£¨¡¡¡¡£©
¢Ù¹ýÑõ»¯ÄÆÓëË®·´Ó¦?¢ÚÄÆÔÚÑõÆøÖÐȼÉÕ?¢ÛÑõ»¯¸ÆÓëË®·´Ó¦?¢ÜCOȼÉÕ?¢ÝÌú·ÛÓëFeCl3ÈÜÒº·´Ó¦£®
A£®¢Ù¢Ú¢Ü¢Ý
B£®¢Ú¢Ü¢Ý
C£®¢Ú¢Û¢Ü¢Ý
D£®¢Ù¢Ú¢Û¢Ü

3¡¢Ñ¡ÔñÌâ  ÔÚÏÂÁÐÖ±½Óת»¯¹ý³ÌÖУ¬ÄÆÔªËØ·¢Éú»¹Ô­·´Ó¦µÄÊÇ£¨¡¡¡¡£©
A£®Na¡úNa2O2
B£®Na¡úNaOH
C£®NaCl¡úNa
D£®NaOH¡úNa2SO4

4¡¢Ìî¿ÕÌâ  Ca£¨ClO£©2ÓëŨÑÎËá·´Ó¦»áÉú³ÉCl2£¬¸Ã·´Ó¦µÄ»¯Ñ§·½³ÌʽΪ£ºCa£¨ClO£©2+4HCl£¨Å¨£©=CaCl2+2Cl2¡ü+2H2O
£¨1£©Å¨ÑÎËáÔÚ·´Ó¦ÖÐÏÔʾ³öÀ´µÄÐÔÖÊÊÇ______?£¨Ìîд×Öĸ£©
A£®Ö»Óл¹Ô­ÐÔ?B£®»¹Ô­ÐÔºÍËáÐÔ?C£®Ö»ÓÐÑõ»¯ÐÔ?D£®Ñõ»¯ÐÔºÍËáÐÔ
£¨2£©²úÉú0.3molCl2£¬ÔòתÒƵĵç×ÓµÄÎïÖʵÄÁ¿Îª______
£¨3£©¸Ã·´Ó¦ÖÐÑõ»¯²úÎïÓ뻹ԭ²úÎïµÄÖÊÁ¿±ÈΪ______
£¨4£©ÓÃË«ÏßÇÅ·¨±íʾ¸ÃÑõ»¯»¹Ô­·´Ó¦Öеç×ÓתÒƵķ½ÏòºÍÊýÄ¿______£®

5¡¢Ìî¿ÕÌâ  Ñõ»¯»¹Ô­·´Ó¦µÄÌØÕ÷ÊÇ______£»ÊµÖÊÊÇ______£»µç×ÓµÄתÒÆÊÇ´Ó______µ½______£®