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????ìa ò??a2FeCl3 + 2KI = 2FeCl2 + 2KCl + I2￡?H2S + I2 =" 2HI" + S￡???áDDeê? ?yè·μ?ê?
A.???ˉD?￡oFe3+￡?I2￡?S
B.???ˉD?￡oI2￡?S￡?Fe3+
C.?1?-D?￡oFe2+￡?I￡-￡?H2S
D.?1?-D?￡oFe2+￡?H2S￡?I￡-
????ì a ò??a2FeCl3 + 2KI = 2FeCl2 + 2KCl + I2￡?H2S + I2 =" 2HI" + S￡???áDDeê??yè·μ?ê?
A.???ˉD?￡oFe3+￡?I2￡?S
B.???ˉD?￡oI2￡?S￡?Fe3+
C.?1?-D?￡oFe2+￡?I￡-￡?H2S
D.?1?-D?￡oFe2+￡?H2S￡?I￡-
±?ìa′e°?￡oA
±?ìa?a??￡o?ù?Y???ˉD?￡o???ˉ?á>???ˉ2ú??￡??1?-D?￡o?1?-?á>?1?-2ú???éí?μ??￡???ˉD?￡oFe3+￡?I2￡?S￡????1?-D?￡oFe2+<I￡-<H2S
±?ìa?ùê???μ?￡o???ˉ?§?ù±???????
±?ìa??ò×3ì?è￡o???òμ￥??
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